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- #include <iostream>
- #include <algorithm>
- #include <cstdlib>
- #include <string>
- #include <sstream>
- using namespace std;
- int main()
- {
- string en;
- int n;
- getline(cin, en);
- stringstream cast(en);
- cast >> n; // get the length of the array we are manipulating
- int * a = (int *) malloc(n * sizeof(int));
- int * b = (int *) malloc(n * sizeof(int));
-
- for (int i = 0; i < n; ++i)
- {
- // get each line which is 2 ints, put into A and B
- string input;
- getline(cin, input);
- stringstream nums(input);
-
- nums >> a[i];
- nums >> b[i];
- }
-
- int clen = (n * (n + 1)) / 2; // total possible sums in an array of length n
- int * c = (int *) malloc(clen * sizeof(int));
- int tempcount = 0;
-
- // Store within c the possible sums inside b
- for (int i = 0; i < n; ++i)
- {
- for (int j = i; j < n; ++j, ++tempcount)
- {
- c[tempcount] = b[i] + b[j];
- }
- }
-
- // sort c, with time complexity n squared log (n squared), which reduces to n squared log n
- sort(c, c + clen);
-
- // for reach sum in a, see if it is in c. n squared checks of log (n squared), or n squared log n
- for (int i = 0; i < clen; ++i)
- {
- for (int j = i; j < n; ++j)
- {
- if (binary_search(c, (c + clen), (a[i] + a[j])))
- {
- free(a); free (b); free(c);
- cout << "TRUE" << endl;
- return 0;
- }
- }
- }
-
- free(a); free(b); free(c);
- cout << "FALSE" << endl;
- return 0;
- }
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