/*
 * Copyright (c) 2000, 2001, 2002, 2003, 2004, 2005, 2008, 2009
 *	The President and Fellows of Harvard College.
 *
 * Redistribution and use in source and binary forms, with or without
 * modification, are permitted provided that the following conditions
 * are met:
 * 1. Redistributions of source code must retain the above copyright
 *    notice, this list of conditions and the following disclaimer.
 * 2. Redistributions in binary form must reproduce the above copyright
 *    notice, this list of conditions and the following disclaimer in the
 *    documentation and/or other materials provided with the distribution.
 * 3. Neither the name of the University nor the names of its contributors
 *    may be used to endorse or promote products derived from this software
 *    without specific prior written permission.
 *
 * THIS SOFTWARE IS PROVIDED BY THE UNIVERSITY AND CONTRIBUTORS ``AS IS'' AND
 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
 * ARE DISCLAIMED.  IN NO EVENT SHALL THE UNIVERSITY OR CONTRIBUTORS BE LIABLE
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 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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 */

/* matmult.c 
 *    Test program to do matrix multiplication on large arrays.
 *
 *    This version uses a storage-inefficient technique to get a
 *    shorter running time for the same memory usage.
 *
 *    Intended to stress virtual memory system.
 *
 *    Once the VM system assignment is complete your system should be
 *    able to survive this.
 */

#include <unistd.h>
#include <stdio.h>

#define Dim 	72	/* sum total of the arrays doesn't fit in 
			 * physical memory 
			 */

#define RIGHT  8772192		/* correct answer */

int A[Dim][Dim];
int B[Dim][Dim];
int C[Dim][Dim];
int T[Dim][Dim][Dim];

int
main()
{
    int i, j, k, r;

    for (i = 0; i < Dim; i++)		/* first initialize the matrices */
	for (j = 0; j < Dim; j++) {
	     A[i][j] = i;
	     B[i][j] = j;
	     C[i][j] = 0;
	}

    for (i = 0; i < Dim; i++)		/* then multiply them together */
	for (j = 0; j < Dim; j++)
            for (k = 0; k < Dim; k++)
		T[i][j][k] = A[i][k] * B[k][j];

    for (i = 0; i < Dim; i++)
	for (j = 0; j < Dim; j++)
            for (k = 0; k < Dim; k++)
		C[i][j] += T[i][j][k];

    r = 0;
    for (i = 0; i < Dim; i++)
	    r += C[i][i];

    printf("matmult finished.\n");
    printf("answer is: %d (should be %d)\n", r, RIGHT);
    if (r != RIGHT) {
	    printf("FAILED\n");
	    return 1;
    }
    printf("Passed.\n");
    return 0;
}